A small electromagnetic pulse weapon (EMP) is detonated dozens of miles away, but it generates a momentary electric field (named “E1”) that has magnitude of 30,000 Volts/meter. In the ensuing seconds the weapon ionizes air molecules that then rise rapidly. This causes a temporary (but rapid) change in the Earth’s magnetic field (named “E3”). Why would a rapidly changing magnetic field (on a city or county scale area) cause current surges in power transmission lines?

A mass spectrometer is used to examine the isotopes of uranium. Ions in the beam emerge from the velocity selector at a speed of 2.96 ✕ 105 m/s and enter a uniform magnetic field of 0.605 T directed perpendicularly to the velocity of the ions. What is the distance between the impact points formed on the photographic plate by singly charged ions of 235U and 238U??? cm

The electric field between the plates of a gear selector in a mass spectrometer is 1×105 V/m. The magnetic field of the speed selector is the same as that of the spectrometer. A beam of +e charged neon ions leaving the speed selector moves in a circular path in the spectrometer before hitting the photographic plate. After a certain time, three spots are observed at distances of 7.4 cm, 7.8 cm and 8.15 cm, respectively.Find the magnetic field assuming that the difference in mass between two isotopes is 1 amu (atomic mass unit):Select the correct answer:

The Venus flytrap (Dionaea muscipula) is a carnivorous plant native to the East Coast of the United States. The plant uses rapid electrical signaling to close its leaf traps when triggered by an insect. This signaling generates action potentials like those in human nerve and muscle cells. The figure shows a trap’s action potential in green, and its corresponding magnetic field in blue (Fabricant et al., 2021). Such measurements of plant magnetic fields could be used in future plant diagnostics, just as MRIs are used in medical imaging today. If the resistance (R) of the trap is 0.97 x 106 Ω, and the action potential is V = 9 x 10-3 V, what is the current (I)? Show your calculations below and give your answer to two significant figures with the units. Hint: use Ohm’s law: I = V/R, substitute the given values to find the current (I) in amperes (A).   Calculations: Answer: