A snowmobile is originally at the point with position vector 26.3 m at 95.0° counterclockwise from the x axis, moving with velocity 4.89 m/s at 40.0°. It moves with constant acceleration 2.02 m/s2 at 200°. After 5.00 s have elapsed, find the following. (Express your answers in vector form.) (a) its velocity vector

A snowmobile is originally at the point with position vector 26.3 m at 95.0° counterclockwise from the x axis, moving with velocity 4.89 m/s at 40.0°. It moves with constant acceleration 2.02 m/s2 at 200°. After 5.00 s have elapsed, find the following. (Express your answers in vector form.) (a) its velocity vector

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 3P: A particle initially located at the origin has an acceleration of a=3.00jm/s2 and an initial...

See similar textbooks

Similar questions

Suppose that a particle begins its motion from the origin and meets the velocity (in m / s) given by: vx (t) = 2.50t vy (t) = 3.50√t. for t> 0 in seconds. Find the speed of the particle at t = 5.00 s What is the acceleration vector (in rectangular components) at t = 2.00 s ? Find the magnitude of the displacement between t = 0.00 s and t = 6.00 s
A snowmobile is originally at the point with position vector 27.1 m at 95.0° counterclockwise from the x axis, moving with velocity 4.13 m/s at 40.0°. It moves with constant acceleration 15 m at 200 After 5.00 s have elapsed, find the following. (Express your answers in vector form.) (a) its velocity vector (b) its position vector
. A snowmobile is originally at the point with position vector 29.0 m at 95.0 degrees counterclockwise from the x axis, moving with velocity 4.50 m/s at 40.0 degrees. It moves with constant acceleration 1.90 m/s^2 at 200 degrees. After 5.00 s have elapsed, find (a) its velocity and (b) its position vector.
A snowmobile is originally at the point with position vector 30.5 m at 95.0° counterclockwise from the x-axis, moving with velocity 4.89 m/s at 40.0°. It moves with a constant acceleration 1.72 m/s2 at 200°. After 5.00 s have elapsed, find the following. (Express your answers in vector form.) (a) its velocity vector. (b) its position vector.
A snowmobile is originally at the point with position vector 29.0 m at 95.0° counterclockwise from the x-axis, moving with velocity 4.50 m/s at 40.0°. It moves with constant acceleration 1.90 m/s 2 at 200°. After 5.00 s have elapsed, find: (a) Its velocity vector (b) Its position vector.
Solving equations of motion Given an acceleration vector,initial velocity ⟨u0, v0, w0⟩, and initial position ⟨x0, y0, z0⟩, find thevelocity and position vectors, for t ≥ 0. a(t) = ⟨sin t, cos t, 1⟩, ⟨u0, v0, w0⟩ = ⟨0, 2, 0⟩,⟨x0, y0, z0⟩ = ⟨0, 0, 0⟩
The coordinates of a particle moving in the XY plane are given as function of time by: X = 5m + ( 7 m/s^4) t ^4 Y = ( 10 m/s)t + (3 m/s^5)t ^5 Find the position vector of the body at t = 3.5 seconds and instantaneous acceleration of the body at t = 3.5 sec
A snowmobile is originally at the point with position vector 31.3 m at 95.0° counterclockwise from the x axis, moving with velocity 4.81 m/s at 40.0°. It moves with constant acceleration 1.87 m/s2 at 200°. After 5.00 s have elapsed, find the following. (a) its velocity vector (b) its position vector
The acceleration of a particle moving only on a horizontal xy plane is given by a→=4ti^+5tj^, where a→ is in meters per second-squared and t is in seconds. At t = 0, the position vector r→=(28.0m)i^+(48.0m)j^ locates the paticle, which then has the velocity vector v→=(6.70m/s)i^+(2.30m/s)j^. At t = 4.60 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?
A snowmobile is originally at the point with position vector 29.0 m at 95.08 counterclockwise from the x axis, moving with velocity 4.50 m/s at 40.0 degrees. It moves with constant acceleration 1.90 m/s2 at 200 degrees. After 5.00 s have elapsed, find (a) its velocity and (b) its position vector.
The position r→ of a particle moving in an xy plane is given by r→=(3.00t^3−7.00t)i^+(6.00−2.00t^4)j^ with r→ in meters and t in seconds. In unit-vector notation, calculate(a)r→, (b)v→, and (c)a→ for t = 2.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 2.00 s? Give your answer in the range of (-180o; 180o).
Suppose that a dove is flying so that its acceleration vector at time t is given by a(t)=<t^4, t^3, t^2>, its initial velocity is v(0)=<1,2,3> and its initial displacement is s(0)=<7,6,5>. Find the position vector s(t) at time t.