A soccer player at 40 m/s and 49 degrees abovethe horizontalWhat is the hang timeRangeAnd max height|The second one was like a car runs off the edgeof a table that is 3m High and lands at 2m fromthe tableAhah is the time it took to fall, what was thespeed before it fell off the edge, and the speed itwent in the horizontal direction before it reachedthe ground

Question
Asked Nov 8, 2019
A soccer player at 40 m/s and 49 degrees above
the horizontal
What is the hang time
Range
And max height|
The second one was like a car runs off the edge
of a table that is 3m High and lands at 2m from
the table
Ahah is the time it took to fall, what was the
speed before it fell off the edge, and the speed it
went in the horizontal direction before it reached
the ground
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A soccer player at 40 m/s and 49 degrees above the horizontal What is the hang time Range And max height| The second one was like a car runs off the edge of a table that is 3m High and lands at 2m from the table Ahah is the time it took to fall, what was the speed before it fell off the edge, and the speed it went in the horizontal direction before it reached the ground

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Expert Answer

Step 1

Hang time of projectile is,

2usin
t =
2( 40 m/s)(sin 49°
9.8m/s
= 6.2s
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2usin t = 2( 40 m/s)(sin 49° 9.8m/s = 6.2s

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Step 2

Range of projectile is,

usin 20
R =
_(40m/s)*(sin 2 (49°))
9.8m/s
161.7m
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usin 20 R = _(40m/s)*(sin 2 (49°)) 9.8m/s 161.7m

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Step 3

Maximum height of pr...

u-sin20
H
2g
(40m/s)'(sin 49°)
2(9.8m/s?)
= 46.5 m
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u-sin20 H 2g (40m/s)'(sin 49°) 2(9.8m/s?) = 46.5 m

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