A sodium sulfate solution is added to a 25.0 mL sample of a solution containing Ba2+ ions until no more precipitate formed. The precipitate (BaSO4) is collected, dried, and weighed. If 1.74 g of the precipitate are obtained, what is the concentration (in M) of Ba2+ ions in the 25.0 mL sample? Your answer should have 3 sig. figs. Molar Masses: (Na2SO4: 142.05 g/mol) (Ba2+: 137.3 g/mol) (BaSO4: 233.37 g/mol
A sodium sulfate solution is added to a 25.0 mL sample of a solution containing Ba2+ ions until no more precipitate formed. The precipitate (BaSO4) is collected, dried, and weighed. If 1.74 g of the precipitate are obtained, what is the concentration (in M) of Ba2+ ions in the 25.0 mL sample? Your answer should have 3 sig. figs. Molar Masses: (Na2SO4: 142.05 g/mol) (Ba2+: 137.3 g/mol) (BaSO4: 233.37 g/mol
General Chemistry - Standalone book (MindTap Course List)
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Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.116QP: Bone was dissolved in hydrochloric acid, giving 50.0 mL of solution containing calcium chloride,...
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A sodium sulfate solution is added to a 25.0 mL sample of a solution containing Ba2+ ions until no more precipitate formed. The precipitate (BaSO4) is collected, dried, and weighed. If 1.74 g of the precipitate are obtained, what is the concentration (in M) of Ba2+ ions in the 25.0 mL sample?
Your answer should have 3 sig. figs.
Molar Masses: (Na2SO4: 142.05 g/mol) (Ba2+: 137.3 g/mol) (BaSO4: 233.37 g/mol
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