A special class of first-order linear equations have the form a(t)y'(t) + a'(t)y(t) = f(t), where a and f are given functions of t. Notice that the left side of this equation can be written as the derivative of a product, so the equation has the form (a(t)y(t)) = a(t)y'(t) + a'(t)y(t) = f(t). Therefore, the equation can be solved by integrating both sides with respect to t. Use this idea to solve the following. 2ty (t) + 2y= 5+ 5t, y(1) = 7 y(t) =. where t>0

Linear Algebra: A Modern Introduction
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Chapter4: Eigenvalues And Eigenvectors
Section4.6: Applications And The Perron-frobenius Theorem
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A special class of first-order linear equations have the form a(t)y'(t) + a'(t)y(t) = f(t), where a and f are given functions of t. Notice that the left side of
d.
this equation can be written as the derivative of a product, so the equation has the form (a(t)y(t)) = a(t)y'(t) + a'(t)y(t) = f(t). Therefore, the
equation can be solved by integrating both sides with respect to t. Use this idea to solve the following.
he form
2ty'(t) + 2y = 5 + 5t, y(1) = 7
y(t) =
where t> 0
Transcribed Image Text:A special class of first-order linear equations have the form a(t)y'(t) + a'(t)y(t) = f(t), where a and f are given functions of t. Notice that the left side of d. this equation can be written as the derivative of a product, so the equation has the form (a(t)y(t)) = a(t)y'(t) + a'(t)y(t) = f(t). Therefore, the equation can be solved by integrating both sides with respect to t. Use this idea to solve the following. he form 2ty'(t) + 2y = 5 + 5t, y(1) = 7 y(t) = where t> 0
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