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Social ScienceA steel container of mass 160 g contains 26.0 g of ammonia, NH2, which has a molar mass of 17.0 g/mol. The container and gasare in equilibrium at 19.0°C. How much heat (in J) has to be removed to reach a temperature ofvolume of the steel. (The specific heat of steel is 452 J/(kg °C). Enter the magnitude.)20.0°C? Ignore the change in
Can you show me this solution, I’m not sure how to work this problem.
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A steel container of mass 160 g contains 26.0 g of ammonia, NH2, which has a molar mass of 17.0 g/mol. The container and gas are in equilibrium at 19.0°C. How much heat (in J) has to be removed to reach a temperature of volume of the steel. (The specific heat of steel is 452 J/(kg °C). Enter the magnitude.) 20.0°C? Ignore the change in
Expert Answer
Given:
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Mass of steel container, m160 g 160 x10 kg Mass of Ammonia,m = 26.0g = 26.0 x 103 kg Molar mass of ammonia,=17.0 g/mol=17.0 x 10 kg/mol Specific heat of steel, C 452 J/kg.K Initial temperature, T 19.0°C Final temperature, T =-20.0°C
Calculation:
The amount of heat for ammonia is given by,
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Q =nC,AT Where n Number of moles C, Specific heat AT Differencein temperature
The amount of heat for s...
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Q mC,AT Where Mass of steel m CSpecific heat of steel AT Differencein temperature
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