Asked Oct 4, 2019

A stone is thrown horizontally from the top of a cliff. A quarter of a second after leaving your hand it drops vertical distance of ___ m from the release point. 

Express you answer to 2 significant figures. The stone is in free fall, g = 10 m/s2


Expert Answer

Step 1


A Ball is thrown horizontally.

Step 2

Calculating the vertical distance traveled by the ball after quarter ...


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Initial vertical velocity of the ball, u = 0 m/s Vertical Acceleration of the ball, a =g 10 m/s2 1/4th of a second 0.25 s Time taken, t 1 Using second equation of motion, S ut+-at Substitute S h, uv = 0 m/s and a = g = 10 m/s2 and t 0.25 s h 0x(10)x (0.25) h 0.3125m h 0.31m (Answer in 2 significant firgures)


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