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A stone is thrown with an initial speed of 15 m/s at an angle of 53 ° above the horizontal from the top of a 35 m building. If g = 9.8 m/s 2 and air resistance is negligible, then what is the magnitude of the horizontal component of velocity as the rock strikes the ground? a.7.5 m/s b.9.0 m/s c.29 m/s d.12 m/s

Question

A stone is thrown with an initial speed of 15 m/s at an angle of 53 ° above the horizontal from the top of a 35 m building. If g = 9.8 m/s 2 and air resistance is negligible, then what is the magnitude of the horizontal component of velocity as the rock strikes the ground?

a.
7.5 m/s

b.
9.0 m/s

c.
29 m/s

d.
12 m/s

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Step 1

The stone is in projectile motion. The stone has no acceleration in the horizontal direction since it is falling under gravity alone which acts in vertical direction. Since the stone has no acceleration in horizontal direction, its horizontal component of velocity will be the same throughout the motion or the velocity of the stone in horizontal direction as it strikes the ground will be equal to its initial horizontal velocity. The equation for the horizontal velocity of a projectile is given by

V =cose
Here, v is the horizontal component of velocity, v is the initial speed and 0 is the angle of launch
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V =cose Here, v is the horizontal component of velocity, v is the initial speed and 0 is the angle of launch

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Step 2

Substitute the numerical values...

(15 m/s) cos 53°
9.0 m/s
The answer is (b).
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(15 m/s) cos 53° 9.0 m/s The answer is (b).

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Science

Physics

Newtons Laws of Motion

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