A stone is thrown with an initial velocity of 35 ft/s from the edge of a bridge that is 43 fr above the ground. The height of this stone above the ground t seconds after it is thrown is f(t)=-16t2+35t+43. If a second stone is thrown from the ground, then its height above the ground after t seconds is given g(t)=-16t2+v0t, where v0 is the initial velocity of the second stone. Determine the value of v0 such that the two stones reach the same high point

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differential equations.