# A stone is tossed in the air from ground level with an initial velocity of 2525 m/sm/s. Its height at time tt is h(t)=25t−4.9t2h(t)=25t−4.9t2 mm.Compute the stone's average velocity over the time interval [0.5,3][0.5,3].Average velocity = ?

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A stone is tossed in the air from ground level with an initial velocity of 2525 m/sm/s. Its height at time tt is h(t)=25t−4.9t2h(t)=25t−4.9t2 mm.

Compute the stone's average velocity over the time interval [0.5,3][0.5,3].

Average velocity = ?

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Step 1

Refer to the question

Stone is tossed with the initial velocity 25m/s and height at an time is h(t) = 25t-4.9t^2.Also the time interval is [0.5,3].

Step 2

Now average velocity is calculated as change in height divided by change in time.

Step 3

Now calculate the height fo...

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