Question
Asked Sep 9, 2019
74 views

A stone is tossed in the air from ground level with an initial velocity of 2525 m/sm/s. Its height at time tt is h(t)=25t−4.9t2h(t)=25t−4.9t2 mm.

Compute the stone's average velocity over the time interval [0.5,3][0.5,3].

Average velocity = ?

check_circle

Expert Answer

Step 1

Refer to the question

Stone is tossed with the initial velocity 25m/s and height at an time is h(t) = 25t-4.9t^2.Also the time interval is [0.5,3].

help_outline

Image Transcriptionclose

= 25t - 4.9t*

fullscreen
Step 2

Now average velocity is calculated as change in height divided by change in time.

help_outline

Image Transcriptionclose

cverage velocity= change in (h change in (t

fullscreen
Step 3

Now calculate the height fo...

help_outline

Image Transcriptionclose

h(t) 25t4.9 Att=0.5 h 11.275 Att 3 h(3) 25(3)-4.9(3) 30.9

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Math

Calculus

Other