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PhysicsQ&A LibraryA student is running at her top speed of 5.5 m/s to catch a Shuttle bus, which is stopped at the bus stop. When the student is still a distance 41.4 m from the Shuttle bus, it starts to pull away, moving with a constant acceleration of 0.177 m/s2 Part A For how much time does the student have to run at 5.5 m/s before she overtakes the bus? t= s Part B For what distance does the student have to run at 5.5 m/s before she overtakes the bus? d= m Part C When she reaches the bus, how fast is the bus traveling? v= m/s Part D What is the minimum speed the student must have to just catch up with the bus? v= m/s Part E For what time does she have to run in that case? t= s Part F For what distance does she have to run in that case? d= mStart your trial now! First week only $4.99!*arrow_forward*

Question

A student is running at her top speed of 5.5 m/s to catch a Shuttle bus, which is stopped at the bus stop. When the student is still a distance 41.4 m from the Shuttle bus, it starts to pull away, moving with a constant acceleration of 0.177 m/s2

For how much time does the student have to run at 5.5 m/s before she overtakes the bus?

t= s

For what distance does the student have to run at 5.5 m/s before she overtakes the bus?

d= m

When she reaches the bus, how fast is the bus traveling?

v= m/s

What is the *minimum* speed the student must have to just catch up with the bus?

v= m/s

For what time does she have to run in that case?

t= s

For what distance does she have to run in that case?

d= m

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