A student is running at her top speed of 5.5 m/s to catch a Shuttle bus, which is stopped at the bus stop. When the student is still a distance 41.4 m from the Shuttle bus, it starts to pull away, moving with a constant acceleration of 0.177 m/s2 Part A For how much time does the student have to run at 5.5 m/s before she overtakes the bus?   t=    s   Part B For what distance does the student have to run at 5.5 m/s before she overtakes the bus? d=   m   Part C When she reaches the bus, how fast is the bus traveling?   v=   m/s   Part D What is the minimum speed the student must have to just catch up with the bus?   v=    m/s   Part E For what time does she have to run in that case? t=    s Part F For what distance does she have to run in that case?   d=   m

Question

A student is running at her top speed of 5.5 m/s to catch a Shuttle bus, which is stopped at the bus stop. When the student is still a distance 41.4 m from the Shuttle bus, it starts to pull away, moving with a constant acceleration of 0.177 m/s2

Part A

For how much time does the student have to run at 5.5 m/s before she overtakes the bus?
 
t=    s
 

Part B

For what distance does the student have to run at 5.5 m/s before she overtakes the bus?

d=   m

 

Part C

When she reaches the bus, how fast is the bus traveling?
 
v=   m/s
 

Part D

What is the minimum speed the student must have to just catch up with the bus?
 
v=    m/s
 

Part E

For what time does she have to run in that case?

t=    s

Part F

For what distance does she have to run in that case?
 
d=   m

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