A student performs a ballistic pendulum experiment using an apparatus similar to that shown in the first figure. She obtains the following averagedata: h = 8.32 cm, projectile mass m, = 62.0 g, and pendulum mass m, = 263 g.VIAof the projectile.(a) Determine the initial speed v1Am/s(b) The second part of her experiment is to obtain v,A by firing the same projectile horizontally (with the pendulum removed from the path)and measuring its horizontal position x and distance of fall y, as shown in the second figure. What numerical value does she obtain for v,, onthe basis of her measured values of x = 264 cm and y = 79.4 cm?m/s

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Asked Dec 6, 2019
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A student performs a ballistic pendulum experiment using an apparatus similar to that shown in the first figure. She obtains the following average
data: h = 8.32 cm, projectile mass m, = 62.0 g, and pendulum mass m, = 263 g.
VIA
of the projectile.
(a) Determine the initial speed v
1A
m/s
(b) The second part of her experiment is to obtain v,A by firing the same projectile horizontally (with the pendulum removed from the path)
and measuring its horizontal position x and distance of fall y, as shown in the second figure. What numerical value does she obtain for v,, on
the basis of her measured values of x = 264 cm and y = 79.4 cm?
m/s
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A student performs a ballistic pendulum experiment using an apparatus similar to that shown in the first figure. She obtains the following average data: h = 8.32 cm, projectile mass m, = 62.0 g, and pendulum mass m, = 263 g. VIA of the projectile. (a) Determine the initial speed v 1A m/s (b) The second part of her experiment is to obtain v,A by firing the same projectile horizontally (with the pendulum removed from the path) and measuring its horizontal position x and distance of fall y, as shown in the second figure. What numerical value does she obtain for v,, on the basis of her measured values of x = 264 cm and y = 79.4 cm? m/s

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Expert Answer

Step 1

(a)

From the conservation of linear momentum,

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+ 0=(m;+m,)V3 m;V1A m,+m, V2gh m, V1A

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Step 2

Substituting the values gives

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62.0g+263g 2(9.8m/s² )(0.0832m) VIA 62.0g = 6.7m/s

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Step 3

(b)

From kinematic e...

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x= x,+v,0+ 0 y=y,*,* y = yo+v30

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