A student used a piece of aluminum that had a mass of 2.583 grams, and treated according to the same procedure you used in this experiment.
2 Al(s) + 2 KOH(aq) + 4 H2SO4(aq) + 22 H2O(l) → 2 KAl(SO4)2•12H2O(s) + 3 H2(g)

What is the mass of Alum theoretically possible? (Hint – Use the molar mass of the alum calculated in question #1.)

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