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A study was performed to investigate the shear strength of soil (y) as it related to depth in feet (x1) and moisture content (x). Ten observations were collected, and the following summary quantities obtained: n = 10, Ex = 223, Ex2 = 553, Ey, = 1,916, Ex = 5,200.9, Ex = 31,729, Ex2 = 12,352, Exy; = 43,550.8, x2y; = 104,736.8, and Ey = 371,595.6. Set up the least squares normal equations for the model y= B, + B,x, + Bx2 + e.

A study was performed to investigate the shear strength of soil (y) as it related to depth in feet (x1) and moisture content (x). Ten observations were collected, and the following summary quantities obtained: n = 10, Ex = 223, Ex2 = 553, Ey, = 1,916, Ex = 5,200.9, Ex = 31,729, Ex2 = 12,352, Exy; = 43,550.8, x2y; = 104,736.8, and Ey = 371,595.6. Set up the least squares normal equations for the model y= B, + B,x, + Bx2 + e.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 93E
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A study was performed to investigate the shear strength of soil (y) as it related to depth in feet (x1) and moisture content (x). Ten observations were collected, and the following summary quantities obtained: n = 10, Exn = 223, Ex2 = 553, Ey, = 1,916, Ex = 5,200.9, E = 31,729, Ex*2 = 12,352, Ex„y; = 43,550.8, Ex2Y; = 104,736.8, and E} = 371,595.6. Set up the least squares normal equations for the model y = B, + B,x1 + Bx2 + e. n 3D а. none о ъ. у-171.054+3-714(х1)-1.126 (х2) O c. y=179.834+4.427(x1)-2.221(x2) O d. y=163.021+3.273(x1)-1.621(x2)
Transcribed Image Text:A study was performed to investigate the shear strength of soil (y) as it related to depth in feet (x1) and moisture content (x). Ten observations were collected, and the following summary quantities obtained: n = 10, Exn = 223, Ex2 = 553, Ey, = 1,916, Ex = 5,200.9, E = 31,729, Ex*2 = 12,352, Ex„y; = 43,550.8, Ex2Y; = 104,736.8, and E} = 371,595.6. Set up the least squares normal equations for the model y = B, + B,x1 + Bx2 + e. n 3D а. none о ъ. у-171.054+3-714(х1)-1.126 (х2) O c. y=179.834+4.427(x1)-2.221(x2) O d. y=163.021+3.273(x1)-1.621(x2)
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