Question
Asked Dec 2, 2019
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A system initially at 1.50L changes its volume under an external pressure of 0.988atm while absorbing 156J of heat to cause an increase in its internal energy by 21 J. What is the final volume, in L, of the system?

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Expert Answer

Step 1

Given data:

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Initial volume (V =1.50 L External pressure(P) = 0.988 atm Heat Absorbed (dQ)=156 J Internal energy (dU)=21J

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Step 2

According to first law of thermodynamic:

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(1) Where sQ is amount of heat absorbed. dU is the intinternal energy sW is the work done by system.

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Step 3

Substitute the value of heat absorbed and...

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sQ = dU +8W 156 J 21J+SW SW 156 J -21 J 135 J

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