Question
Asked Sep 10, 2019

A teenager climbs a tree that is 40ft tall. Once at the top of the tree he drops a ball that takes 2 seconds to hit the ground. Determine its initial and final speeds. 

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Expert Answer

Step 1
The ball when dropped from the tree, will be under gravity. The equation of motion is given by
1
s = ut at
2
Here, s is the displacement, is the initial velocity, is the time and a is the acceleration.
Take the upward direction to be positive. The value of acceleration will be equal to the negative of
acceleration due to gravity
1
s ut g
2
1
= ut
2
ut S gt
2
1
S
(1)
gt
2
t
The value of g is 9.80 m/s2
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The ball when dropped from the tree, will be under gravity. The equation of motion is given by 1 s = ut at 2 Here, s is the displacement, is the initial velocity, is the time and a is the acceleration. Take the upward direction to be positive. The value of acceleration will be equal to the negative of acceleration due to gravity 1 s ut g 2 1 = ut 2 ut S gt 2 1 S (1) gt 2 t The value of g is 9.80 m/s2

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