A three-step process for producing molten iron metal from Fe2O3 is: 3Fe2O3 + CO → 2Fe3O4 + CO2 Fe3O4 + CO → 3FeO + CO2 FeO + CO → Fe + CO2 Assuming that the reactant CO is present in excess and that the yields, respectively, for the three steps are 72.6%, 50.7% and 86.9%, what mass of iron metal would be produced from 190. kg of Fe2O3?
A three-step process for producing molten iron metal from Fe2O3 is: 3Fe2O3 + CO → 2Fe3O4 + CO2 Fe3O4 + CO → 3FeO + CO2 FeO + CO → Fe + CO2 Assuming that the reactant CO is present in excess and that the yields, respectively, for the three steps are 72.6%, 50.7% and 86.9%, what mass of iron metal would be produced from 190. kg of Fe2O3?
Introductory Chemistry: A Foundation
8th Edition
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 19CR
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A three-step process for producing molten iron metal from Fe2O3 is:
- 3Fe2O3 + CO → 2Fe3O4 + CO2
- Fe3O4 + CO → 3FeO + CO2
- FeO + CO → Fe + CO2
Assuming that the reactant CO is present in excess and that the yields, respectively, for the three steps are 72.6%, 50.7% and 86.9%, what mass of iron metal would be produced from 190. kg of Fe2O3?
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