A toroid having a square cross section, 5.73 cm on a side, and an inner radius of 21.3 cm has 400 turns and carries a current of 1.03 A. (It is made up of a square solenoid instead of round one bent into a doughnut shape.) What is the magnitude of the magnetic field inside the toroid at (a) the inner radius and (b) the outer radius?

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Asked Aug 1, 2019
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A toroid having a square cross section, 5.73 cm on a side, and an inner radius of 21.3 cm has 400 turns and carries a current of 1.03 A. (It is made up of a square solenoid instead of round one bent into a doughnut shape.) What is the magnitude of the magnetic field inside the toroid at (a) the inner radius and (b) the outer radius?

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Expert Answer

Step 1

Given:

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Side of square,s = 5.73cm=0.0573m Inner radius,r 21.3cm-0.213m Numberof turns, N 400 Current, I 1.03A

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Step 2

Calculation:

The magnetic field of a toroid at a distance r is given by:

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B MOIN 27Tr

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Step 3

Part (a):

The magnitude of the magnetic...

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HOIN В, 2Tr 4x3.14x10 T.m/A) x1.03(A)x400 В, 2x3.14x0.213(m) B 3.8x10 T

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