Question

Asked Oct 25, 2019

A toy rocket is launched from the top of a building 95 feet tall at an initial velocity of

223 feet per second.

a) Give the function that describes the height of the rocket in terms of time t.

b) Determine the time at which the rocket reaches its maximum height, and the maximum height in feet.

c) For what time interval will the rocket be more than 851 feet above ground level?

d) After how many seconds will it hit the ground?

Step 1

Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and specify the other subparts (up to 3) you’d like answered.

Acceleration due to gravity = 32 feet per second^2

Initial velocity=v0=223 feet per second.

Initial height =h0=95 feet

Height at t second is h(t)

Answer(a): **h(t)=-16t^2+223t+95**

Step 2

When the rocket reaches maximum height then t=-b/(2a) [using vertex formula] With a=-16 and b=223

At t=6.96875 we then find the height....

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