Question
Asked Feb 13, 2020
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(a) Triazine, C3 H3 N3, is like benzene except that in triazine
every other C¬H group is replaced by a nitrogen atom. Draw the Lewis structure(s) for the triazine molecule. (b) Estimate
the carbon–nitrogen bond distances in the ring.

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Expert Answer

Step 1

a). Lewis structure of triazine molecule:

  • The C3H3N3 molecules is like benzene except that in triazine every other C-H group is replaced by a nitrogen atom. The formation of Lewis structure for triazine involves the following steps.
  • Sum the valence electrons of all the atoms to get total number of valence electrons for the molecule. Carbon has 4, nitrogen has 5 and hydrogen has 1 valence electrons.

Thus, the total number of valence electrons in

C3H3N3= 3 x 4 + 3 x 1 + 3 x 5 = 30

Step 2

Triazine is similar to benzene so it has a ring structure with alternate carbon and nitrogen atoms and alternate double and single bonds. Thus, there are three C-N double bonds that use 12 valence electrons and three C-N single bond that use 6 electrons.

  • Each carbon bonds with two nitrogen atoms, one through a double bond and one through a single bond with one H atom that completes the duplet of hydrogen and octet of carbon. Thus, three C-H single bonds are formed using 6 valence electrons.
  • The remaining 30-24 =6 electrons ...

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