A tumor is approximately modeled by the shape of a sphere, given by the following equation: 3 V = = r* (1) where V, is the volume of the spherical tumor and r, the radius. Data shows that, when the diameter of a spherical tumor is 16 mm then it is growing at a rate of 0.4 mm a day. How fast is the volume of the tumor changing at that time, mathematically this is symbolised by the derivative ? Solve the above problem through the following steps: (a) Apply the chain rule to equation 1 to find after writing r as r (t), because r is a function of time, t. Your answer will include r' (t) = 4[4] (b) Information of the size of this tumor is given in diameter measurement, convert this to radius measurement for r and r' (t) = [2] (c) Lastly, substitute the answers of (b) into the "answer equation" that you found in (a), to calculate 12)

A tumor is approximately modeled by the shape of a sphere, given by the following equation: 3 V = = r* (1) where V, is the volume of the spherical tumor and r, the radius. Data shows that, when the diameter of a spherical tumor is 16 mm then it is growing at a rate of 0.4 mm a day. How fast is the volume of the tumor changing at that time, mathematically this is symbolised by the derivative ? Solve the above problem through the following steps: (a) Apply the chain rule to equation 1 to find after writing r as r (t), because r is a function of time, t. Your answer will include r' (t) = 4[4] (b) Information of the size of this tumor is given in diameter measurement, convert this to radius measurement for r and r' (t) = [2] (c) Lastly, substitute the answers of (b) into the "answer equation" that you found in (a), to calculate 12)

Name: A tumor is approximately modeled by the shape of a sphere, given by t
Uploaded: 2024-03-20T06:46:42.000Z
Channel: Bartleby
Description: A tumor is approximately modeled by the shape of a sphere, given by the following equation:3V == r*(1)where V, is the volume of the spherical tumor and r, the radius. Data shows that, when the diameterof a spherical tumor is 16 mm then it is growing