A virus particle has an approximate volume of 5.20 x 106 nm3 and an approximate mass of 1.00 fg. Based on these values only, what is the minimum volume of a container in units of mL needed to contain 1.00 oz (0.0625 Ibs) of virus particles. Note: Scientific notation is optional. To write scientific notation in Canvas, type "e" to replace "x 10". For example "1 x 1014" is written “1e+14" in Canvas. Canvas will automatically convert it out of scientific notation, which is fine.

A virus particle has an approximate volume of 5.20 x 106 nm3 and an approximate mass of 1.00 fg. Based on these values only, what is the minimum volume of a container in units of mL needed to contain 1.00 oz (0.0625 Ibs) of virus particles. Note: Scientific notation is optional. To write scientific notation in Canvas, type "e" to replace "x 10". For example "1 x 1014" is written “1e+14" in Canvas. Canvas will automatically convert it out of scientific notation, which is fine.

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter1: The Nature Of Chemistry

Section: Chapter Questions

Problem 116QRT

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Some bottles of colorless liquids were being labeled when the technicians accidentally mixed them up and lost track of their contents. A 15.0-mL sample withdrawn from one bottle weighed 22.3 g. The technicians knew that the liquid was either acetone, benzene, chloroform, or carbon tetrachloride (which have densities of 0.792 g/cm3, 0.899 g/cm3, 1.489 g/cm3, and 1.595 g/cm3, respectively). What was the identity of the liquid?
An empty Erlenmeyer flask weighs 235.6 g. When filled with water (d = 1.00 g/cm3), the flask and its contents weigh 571.3 g. (a) What is the volume of water in the flask? Enter your answer in scientific notation. (b) How much does the flask weigh when filled with the same volume of chloroform (d = 1.48 g/cm3)?
The German chemist Fritz Haber proposed paying off the reparations imposed against Germany after World War I by extracting gold from seawater. Given the following data, what was the dollar amount of the gold that could have been extracted from 3.0 m3 of seawater? The price of gold at the time was $0.68 per gram of gold. Gold occurs in seawater to the extent of 5.15 x 1011 atoms per gram of seawater. The density of seawater is 1.03 g/cm3.
The mass of an atom of silver is 1.79 × 10-22 g. How many atoms are in a 0.65 lb sample of silver? (Enter your answer in scientific notation as follows: 1.00E+2 is equivalent to 100).
A manufacturer of paint claims that a gallon (3.78L) of latex paint can cover 365 ft2 of the surface of a wall in a single coating. The paint manufacturer also claims that one single coating of an entire wall will be 3.40 mm thick. Is this a case of false advertising? Yes or No? Elaborate your answer by providing a calculation. You may use the following conversions: 12 in = 1 ft, 2.54 = 1 in
An empty Erlenmeyer flask weighs 241.3 g. When filled with water (d 5 1.00 g/cm3), the flask and its contents weigh 489.1 g. (a) What is the flask’s volume? (b) How much does the flask weigh when filled with chloroform (d 5 1.48 g/cm3)?
It has been estimated that there is 4.00 × 10-4 mg of gold per liter of seawater. At price of $19.40/g, what would be the value of the gold in 5.44 km3 (1 km3 = 1 × 1015 cm3) of the ocean?(Enter your answer in scientific notation as follows: 1.00E+2 is equivalent to 100.)
1.state the process determining the volume of irregular object 2.In determining the density of an irregular stone of a mass 80g.The stone was dip in a measuring cylinder fill with water and gave a find reading of 100cm3 after the experiment. The density of a stone was 2g/cm2.Find the initial reading of the measuring cylinder. 3.A solid of mass 450kg has a volume of 20cm3 calculate the relate density of solid. Density of water:100pkg/m3 changes in cm
What is the mass of 4.00 cm^3 of sodium, with a density of 0.97 g/cm^3?
It has been estimated that there is 4.00 × 10-4 mg of gold per liter of seawater. At price of $19.40/g, what would be the value of the gold in 7.53 km3 (1 km3 = 1 × 1015 cm3) of the ocean?
Using the mass of the protonfrom Table 2.1 and assuming its diameter is 1.0 * 10-15 m,calculate the density of a proton in g>cm3.
The diameter of a single carbon particle in a sample of printer toner is 25nm. If you have50g of that carbon, how long of a chain of carbon particles could you string end to end?Assume that the particles are perfect spheres and they all have the same diameter.Volume of a sphere: (4/3)πr3 Density of carbon: 2.0g/cm3The given information and your knowledge of metric prefixes and conversions is the onlyinformation that you will need to solve the problem.

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