A voltaic cell is based on the two standard half-reactions Cd2+1aq2 + 2 e- ¡ Cd1s2 Sn2+1aq2 + 2 e- ¡ Sn1s2 Use data in Appendix E to determine (a) which half-reaction occurs at the cathode and which occurs at the anode

General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.48QP: A mercury battery, used for hearing aids and electric watches, delivers a constant voltage (1.35 V)...
icon
Related questions
Question

A voltaic cell is based on the two standard half-reactions Cd2+1aq2 + 2 e- ¡ Cd1s2 Sn2+1aq2 + 2 e- ¡ Sn1s2 Use data in Appendix E to determine (a) which half-reaction occurs at the cathode and which occurs at the anode

Expert Solution
Step 1

A half reaction can be oxidation or reduction reaction and both the reaction takes place simultaneously in a redox or oxidation-reduction reaction. If the chemical species undergoes chemical reaction by losing of electron, then the species get oxidized and the reaction is called oxidation half reaction. On the other hand, if the chemical species undergoes chemical reaction by gaining electron, then the species get reduced and the reaction is reduction half reaction. When a species undergoes oxidation, then its oxidation number increases and if it undergoes reduction, then its oxidation number decreases.

Step 2

The given standard half reactions are along with its reduction potential in appendix E are,

                             Cd2+(aq) + 2 e- ---> Cd (s)                    Eored = - 0.4 V

                             Sn2+(aq) + 2 e- ----> Sn (s)                   Eored = - 0.14 V

Now, as the reduction potential of Cd is more negative than Sn, hence Cd has more reducing power than Sn, so Cd acts as a reducing agent and reduces Sn at cathode and itself get oxidized at anode.

 

steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
Electrochemical Cells
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
General Chemistry - Standalone book (MindTap Cour…
General Chemistry - Standalone book (MindTap Cour…
Chemistry
ISBN:
9781305580343
Author:
Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:
Cengage Learning
Chemistry: Matter and Change
Chemistry: Matter and Change
Chemistry
ISBN:
9780078746376
Author:
Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:
Glencoe/McGraw-Hill School Pub Co
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:
9781559539418
Author:
Angelica Stacy
Publisher:
MAC HIGHER
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning