A volume of 75.0 mL of H2O is initially at room temperature (22.00 Celcius). A chilled steel rod at 2.00 Celcius is placed in the water. If the final temperature of the system is 21.50 Celcius, what is the mass of the steel bar?Use the following values: specific heat of water= 4.18 J (g x Celcius)Specific heat of steel= 0.452 J (g x Celcius)

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Asked Oct 24, 2019
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A volume of 75.0 mL of H2O is initially at room temperature (22.00 Celcius). A chilled steel rod at 2.00 Celcius is placed in the water. If the final temperature of the system is 21.50 Celcius, what is the mass of the steel bar?

Use the following values: 

specific heat of water= 4.18 J (g x Celcius)

Specific heat of steel= 0.452 J (g x Celcius)

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Expert Answer

Step 1

Given:

Volume of water = 75.0 mL

Density of water = 1 g/...

mass density x volume
mass 1 g/mL x 75.0 mL
mass 75.0 g
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mass density x volume mass 1 g/mL x 75.0 mL mass 75.0 g

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