A water pump increases the water pressure from 15 psia to 80 psia.a. Determine the flow work, in Btu/lbm, required by the pump. Assume thatthe state of the water at pump inlet is saturated liquid and that the specificvolume remains constant during this process.b. Water enters this pump through a 1.5-in-diameter opening and exitsthrough a 2-in-diameter opening. Determine the velocity of the water at theinlet and outlet when the mass flow rate through the pump is 1.1 lbm/s

Question
Asked Oct 24, 2019

A water pump increases the water pressure from 15 psia to 80 psia.

a. Determine the flow work, in Btu/lbm, required by the pump. Assume that
the state of the water at pump inlet is saturated liquid and that the specific
volume remains constant during this process.

b. Water enters this pump through a 1.5-in-diameter opening and exits
through a 2-in-diameter opening. Determine the velocity of the water at the
inlet and outlet when the mass flow rate through the pump is 1.1 lbm/s

check_circleExpert Solution
Step 1

Consider v be the specific volume for the water in the pump. As mentioned in the question that the specific volume remains constant during the process of this pressure change.

Therefore, the specific volume of the water at pressure 15 psia is equal to the specific volume of the water at 80 psia.

Step 2

It is also mentioned in the question that, at the inlet (at pressure of 15 psia) the water is saturated liquid.

Refer the steam table for the saturated water, the value of the specific volume of the saturated liquid water at 15 psia is 0.01672 ft3/lbm.

Step 3

The expression for the flow work, W...

W P,v2-PV
Here, 2
Therefore
W,= v(P -P
W, (0.01672 ft/Ibm (80 psia -15 psia)
f
W, 1.0868 psia ft'/lbm
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W P,v2-PV Here, 2 Therefore W,= v(P -P W, (0.01672 ft/Ibm (80 psia -15 psia) f W, 1.0868 psia ft'/lbm

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