Question

Asked Feb 23, 2019

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A water tank is being drained and has the shape of a rectanuglar box 7m long, 6m wide and 5m high. How fast is the water depth changing when the water depth is 0.9m?

V= 42(60-t)^2

Step 1

We can express the volume of water in the tank after time t in terms of height x of the water in the tank as shown below:

V=7*6*x=42x

Let us find the remaining volume of water when height is x = 0.9:

Step 2

We have been given a rectangular water tank with length 7 m, width 6 m and height 5 m.

We can express the volume of water when height of water in the tank is x meters as V=7*6*x = 42x

Let us now find the rate of change of

Step 3

Let us now find the time when volume is ...

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