A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremelyimportant." A random sample of n, - 41 adults were asked about fishing as an outdoor activity. The mean response was x, = 4.9. Another random sample of n, = 52 adults were askedabout camping as an outdoor activity. For this group, the mean response was x, = 5.7. From previous studies, it is known that o, - 1.6 and o, = 1.9. Does this indicate a difference(either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance.Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they "strongly agree,""agree," "disagree," or "strongly disagree" with the statement.(a) What is the level of significance?State the null and alternate hypotheses.(b) What sampling distribution will you use? What assumptions are you making?The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations.The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations.O The standard normal. We assume that both population distributions are approximately normal with known standard deviations.O The Student's t. We assume that both population distributions are approximately normal with known standard deviations.What is the value of the sample test statistic? (Test the difference u, - H. Round your answer to two decimal places.)(c) Find (or estimate) the P-value. (Round your answer to four decimal places.)Sketch the sampling distribution and show the area corresponding to the P-value.O-3-2-12o-3-2-113o-3-2-1123o-3-2-1123

Name: A Michigan study concerning preference for outdoor activities used a
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremelyimportant." A random sample of n, - 41 adults were asked about

Question

A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated &#34;not important&#34; and 6 designated &#34;extremelyimportant.&#34; A random sample of n, - 41 adults were asked about fishing as an outdoor activity. The mean response was x, = 4.9. Another random sample of n, = 52 adults were askedabout camping as an outdoor activity. For this group, the mean response was x, = 5.7. From previous studies, it is known that o, - 1.6 and o, = 1.9. Does this indicate a difference(either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance.Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they &#34;strongly agree,&#34;&#34;agree,&#34; &#34;disagree,&#34; or &#34;strongly disagree&#34; with the statement.(a) What is the level of significance?State the null and alternate hypotheses.(b) What sampling distribution will you use? What assumptions are you making?The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations.The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations.O The standard normal. We assume that both population distributions are approximately normal with known standard deviations.O The Student's t. We assume that both population distributions are approximately normal with known standard deviations.What is the value of the sample test statistic? (Test the difference u, - H. Round your answer to two decimal places.)(c) Find (or estimate) the P-value. (Round your answer to four decimal places.)Sketch the sampling distribution and show the area corresponding to the P-value.O-3-2-12o-3-2-113o-3-2-1123o-3-2-1123

Accepted Answer

For fishing, sample size n1 = 41, sample mean = 4.9 and population SD = 1.6
For camping, sample size…