A wheel rotates with a constant angular acceleration of 3.45 rad/s2. Assume the angular speed of the wheel is 2.20 rad/s at ti = 0. (a) Through what angle does the wheel rotate between t = 0 and t = 2.00 s? Give your answer in radians and revolutions. 11.3rad 1.80rev (b) What is the angular speed of the wheel at t = 2.00 s? 9.1rad/s (c) What angular displacement (in revolutions) results while the angular speed found in part (b) doubles? 5.80rev   2. Use the values from PRACTICE IT to help you work this exercise. (a) Find the angle through which the wheel rotates between t = 2.00 s and t = 3.10 s.   (b) Find the angular speed when t = 3.10 s. rad/s (c) What is the magnitude of the angular speed five revolutions following t = 3.10 s?

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Angular speed, acceleration and displacement

Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.

Angular Position

Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.