Question
Asked Dec 3, 2019

Determine the stress components acting on the inclined plane AB in if:

normal stressy = 61MPa

shear stressxy = -25 MPa

solve the problem using the method of equilibrium.

Find normal stress x' =?

find shear stress x'y' =?

А.
300
В
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А. 300 В

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Expert Answer

Step 1

Consider the following diagram representing stresses acting on the body. The area of cross-section of the body is A.

61MPA
y(tve)
(tve)
461MPA
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61MPA y(tve) (tve) 461MPA

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Step 2

The body is subjected to uniaxial tensile and shear stress (i.e. acting in the plane x-y) as shown in the above diagram. Consider free body diagram of the section OAB.

Рy
Fyx
30
В
Pn
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Рy Fyx 30 В Pn

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Step 3

Therefore, the magnitude o...

F
ху
-(Fm)4
F
Jх
= F_
The value of F
xy
ух
P -(0,)A
Р,
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F ху -(Fm)4 F Jх = F_ The value of F xy ух P -(0,)A Р,

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