Question

A 0.0280 kg bullet moving horizontally at 400 m/s embeds itself into an initially stationary 0.500 kg block.(a) What is their velocity just after the collision?

m/s

(b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity?

m/s

(c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping?

m

Step 1

a)

From conservation of momentum, the required velocity just after collision is,

Step 2

b)

The acceleration of the system,

Step 3

Now, from kinematics, the r...

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