A 1.00 × 10−2-kg bullet is fired horizontally into a 2.50-kg wooden block attached to one end of a massless horizontal spring (k = 845 N/m). The other end of the spring is fixed in place, and the spring is unstrained initially. The block rests on a horizontal, frictionless surface. The bullet strikes the block perpendicularly and quickly comes to a halt within it. As a result of this completely inelastic collision, the spring is compressed along its axis and causes the block/bullet to oscillate with an amplitude of 0.200 m. What is the speed of the bullet?

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Asked Nov 8, 2019
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A 1.00 × 10−2-kg bullet is fired horizontally into a 2.50-kg wooden block attached to one end of a massless horizontal spring (k = 845 N/m). The other end of the spring is fixed in place, and the spring is unstrained initially. The block rests on a horizontal, frictionless surface. The bullet strikes the block perpendicularly and quickly comes to a halt within it. As a result of this completely inelastic collision, the spring is compressed along its axis and causes the block/bullet to oscillate with an amplitude of 0.200 m. What is the speed of the bullet?

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Expert Answer

Step 1

When the bullet strikes the block the combination results in a certain velocity based on, this sp...

т,
u = v2
(1)
т + т,
(2)
= Aa
max
mass m M2
k
=0.101 2.50
т
= 2.510
845
2.510
-18.348
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т, u = v2 (1) т + т, (2) = Aa max mass m M2 k =0.101 2.50 т = 2.510 845 2.510 -18.348

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