A 65-kg base runner begins his slide into second base when he is moving at a speed of 3.5 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.(a) How much mechanical energy is lost due to friction acting on the runner? (b) How far does he slide?

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Asked Dec 8, 2019
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A 65-kg base runner begins his slide into second base when he is moving at a speed of 3.5 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.

(a) How much mechanical energy is lost due to friction acting on the runner?
 

(b) How far does he slide? 


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Expert Answer

Step 1

a)

the mechanical energy lost is the work done by the runner to reach the base which is equal to the change in kinetic energy.

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Step 2

substitute the known values in the above equation to calculate W

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W = (65kg)(0° -(3.5 m/s)°) = -398.1J

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Step 3

b) 

the work done is equal to W=f*d

the express...

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W = fd f =-umg W =-umgd or - umg

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Friction

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