Activation energy for the reaction is 44KJ/mole. A catalyst is added and the reaction rate constant increases from 34L3mole-3s-1 to 400 L3mole-3s-1 . What is then the activation energy given T = 25 degrees celsius?

Activation energy for the reaction is 44KJ/mole. A catalyst is added and the reaction rate constant increases from 34L3mole-3s-1 to 400 L3mole-3s-1 . What is then the activation energy given T = 25 degrees celsius?

General, Organic, and Biological Chemistry

7th Edition

ISBN:9781285853918

Author:H. Stephen Stoker

Publisher:H. Stephen Stoker

Chapter10: Acids, Bases, And Salts

Section: Chapter Questions

Problem 10.26EP: The formula for tartaric acid is preferably written as H2C4H4O6 rather than as C4H6O6. Explain why.

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Question

Activation energy for the reaction is 44KJ/mole. A catalyst is added and the reaction rate constant increases from 34L³mole^-3s^-1to 400 L³mole^-3s^-1. What is then the activation energy given T = 25 degrees celsius?

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61 (aq) + BrO3(aq) + 6H3O*(aq)→ 312(aq) + Br´(aq) + 9H2O(1)

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