Air T 535°R c= 0.240 Btu/lb-°R Saturated liquid R-134a Tз, тз Wey = -0.2 hp Fan cv Throttling valve 4 5 Saturated vapor P5 P4 P4=60 lbf/in. 2 T2=528°R 2 Heat exchanger

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Chapter7: Forced Convection Inside Tubes And Ducts
Section: Chapter Questions
Problem 7.49P
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The figure belows shows three components of an air-conditioning system, where T3= 115°F and m˙3= 1.5 lb/s. Refrigerant 134a flows through a throttling valve and a heat exchanger while air flows through a fan and the same heat exchanger. Data for steady-state operation are given on the figure. There is no significant heat transfer between any of the components and the surroundings. Kinetic and potential energy effects are negligible.
 
Modeling air as an ideal gas with constant cp = 0.240 Btu/lb · °R, determine the mass flow rate of the air, in lb/s.
Air
T 535°R
c= 0.240 Btu/lb-°R
Saturated liquid R-134a
Tз, тз
Wey = -0.2 hp
Fan
cv
Throttling
valve
4
5
Saturated vapor
P5 P4
P4=60 lbf/in. 2
T2=528°R
2
Heat exchanger
Transcribed Image Text:Air T 535°R c= 0.240 Btu/lb-°R Saturated liquid R-134a Tз, тз Wey = -0.2 hp Fan cv Throttling valve 4 5 Saturated vapor P5 P4 P4=60 lbf/in. 2 T2=528°R 2 Heat exchanger
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