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StatisticsQ&A Libraryall 12%1:19 Y ☺Lab Assignment #8_-150...ANOVAAn experiment was conducted to determine if motivational techniques in management significantly impactedemployee stress levels compared to no intervention. An employee survey was given to three groups: onegroup under a manager who started using a transformational motivation technique, one group under amanager who began using a transformational motivation technique, and then a control group with no newtechnique used. Stress levels were self-reported by the employees as shown below. Use alpha = 0.05TransformationalTransactionalControl26.331. What is your null hypothesis?2. What is your alternative hypothesis?After running the single factor analysis of variance on the data, what is the p-value for between3.groups?Using the 95% significance level, is there a significance difference in stress levels between the three4.groups?5. Do you reject or accept the null hypothesis?YesNoRejectAcceptIIQuestion

Asked Dec 8, 2019

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Step 1

Formulation of hypothesis

1)

Null Hypothesis is :- There is no difference between the mean of stress level among the three groups

H_{0}: µ_{Transformational }= µ_{Transactional }= µ_{control }

2)

Alternative Hypothesis is :- At least one of the group has difference between the mean of stress level.

H_{α}: µ_{Transformational} ≠ µ_{Transactional} ≠µ_{control}

3)

Steps to perform ANOVA in Excel is given below

- Enter the data in Excel as shown below

Step 2

- GO to data->data analysis->select Anova: Single Factor
- Enter the following data in this table

Step 3

Result From ANOVA is...

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