Aluminum Copper Egu = 18(10³) ksi ABC = 0.12 in? Steel E = 29(10³) ksi E = 10(10°) ksi AAB = 0.09 in? AcD = 0.06 in? 3.50 kip 1.75 kip 2.00 kip 1.50 kip D B 3.50 kip 1.75 kip -18 in: -12 in.- -16 in-

Aluminum Copper Egu = 18(10³) ksi ABC = 0.12 in? Steel E = 29(10³) ksi E = 10(10°) ksi AAB = 0.09 in? AcD = 0.06 in? 3.50 kip 1.75 kip 2.00 kip 1.50 kip D B 3.50 kip 1.75 kip -18 in: -12 in.- -16 in-

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter7: Tubing And Piping

Section: Chapter Questions

Problem 2RQ: The size of 1/2 in. would refer to the ______regard to copper tubing used in plumbing and heating....

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Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

Question

The composite shaft, consisting of aluminum, copper, and steel sections, is subjected to the loading shown. Determine the displacement of end A with respect to end D and the normal stress in each section. The cross-sectional
area and modulus of elasticity for each section are shown in the figure. Neglect the size of the collars at B and C.

Aluminum
Copper
Egu = 18(10³) ksi
ABC = 0.12 in?
Steel
E = 29(10³) ksi
E = 10(10°) ksi
AAB = 0.09 in?
AcD = 0.06 in?
3.50 kip
1.75 kip
2.00 kip
1.50 kip
D
B
3.50 kip
1.75 kip
-18 in:
-12 in.-
-16 in-

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