Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) Which reagent is the limiting reactant when 0.500 Al(OH)3 and 0.500mol H2SO4 are allowed to react? Al(OH)3(s)Al(OH)3(s) H2SO4(aq)H2SO4(aq) H2O(l)H2O(l) Al2(SO4)3(aq)Al2(SO4)3(aq) How many moles of Al2(SO4)3Al2(SO4)3 can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) Which reagent is the limiting reactant when 0.500 Al(OH)3 and 0.500mol H2SO4 are allowed to react? Al(OH)3(s)Al(OH)3(s) H2SO4(aq)H2SO4(aq) H2O(l)H2O(l) Al2(SO4)3(aq)Al2(SO4)3(aq) How many moles of Al2(SO4)3Al2(SO4)3 can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.24PAE: 4.24 Ammonia gas can be prepared by the reaction CaO(s)+2NH4Cl(s)2NH3(g)+H2O(g)+CaCl2(s) If 112 g of...
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Aluminum hydroxide reacts with sulfuric acid as follows:
2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l)
Which reagent is the limiting reactant when 0.500 Al(OH)3 and 0.500mol H2SO4 are allowed to react?
| Al(OH)3(s)Al(OH)3(s) |
| H2SO4(aq)H2SO4(aq) |
| H2O(l)H2O(l) |
| Al2(SO4)3(aq)Al2(SO4)3(aq) |
How many moles of Al2(SO4)3Al2(SO4)3 can form under these conditions?
How many moles of the excess reactant remain after the completion of the reaction?
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