Aluminum oxide forms when aluminum reacts with oxygen by the following balanced reaction: 4 Al(s) + 3 O2(g) ⟶  2 Al2O3(s) What is the percent yield if 12.3 g of Al2O3 (MM = 101.96 g/mol) is recovered from reacting 10.0 g of Al (MM = 26.98 g/mol) with an excess of O2?

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Chapter3: Stoichiometry
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Aluminum oxide forms when aluminum reacts with oxygen by the following balanced reaction:

4 Al(s) + 3 O2(g) ⟶  2 Al2O3(s)

What is the percent yield if 12.3 g of Al2O3 (MM = 101.96 g/mol) is recovered from reacting 10.0 g of Al (MM = 26.98 g/mol) with an excess of O2?

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