# An 18 gauge copper wire (diameter 1.02 mm) carries a current with a current density of 2.90×10^6 A/m2. The density of free electrons for copper is 8.5×10^28 electrons per cubic meter.Calculate the current in the wire.Express your answer with the appropriate units.Calculate the magnitude of the drift velocity of electrons in the wire.Express your answer with the appropriate units.

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An 18 gauge copper wire (diameter 1.02 mm) carries a current with a current density of 2.90×10^6 A/m2. The density of free electrons for copper is 8.5×10^28 electrons per cubic meter.

Calculate the current in the wire.
Calculate the magnitude of the drift velocity of electrons in the wire.
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Step 1

The equation for the current in the wire is given by help_outlineImage TranscriptioncloseI JA Here, I is the current, J is the current density and A is the area of cross section The equation for the area of cross section of the wire is given by ла? 4 Here, d is the diameter of the wire. Thus ла'л I 4 Substitute the numerical values in the above equation T(1.02x103 m(2.90 x 10 A/m2) I = 4 = 2.37 A The equation for the drift velocity of the electrons in the wire is given by I neA is the drift velocity, n is the free electron density and e is the magnitude of charge of the Here, electron fullscreen
Step 2

Putting the equatio... help_outlineImage Transcriptionclose41 nd'ne Substitute the numerical values in the above equation. 4(2.37 A) (1.02x10 m) (8.5x102) (1.60 x10" C) 2.13x10 m/s fullscreen

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