An air-gap parallel-plate capacitor that has a plate area of 1.20 m2 and a separation of 1.40 mm is charged to 90 V. (a) What is the electric field between the plates? V kV/m 64.285 (b) What is the electric energy density between the plates? 18.28 v m)/m3 (c) Find the total energy by multiplying your answer from Part (b) by the volume between the plates. 30,72 (d) Determine the capacitance of this arrangement. nF (e) Calculate the total energy from U = 2CV2, and compare your answer with your result from Part (c).

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter27: Capacitors And Batteries
Section: Chapter Questions
Problem 24PQ: An arrangement of capacitors is shown in Figure P27.23. a. If C = 9.70 105 F, what is the...
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please do part d and e

An air-gap parallel-plate capacitor that has a plate area of 1.20 m2 and a separation of 1.40 mm is charged to 90 v.
(a) What is the electric field between the plates?
V kV/m
64.285
(b) What is the electric energy density between the plates?
18.28
v m)/m3
(c) Find the total energy by multiplying your answer from Part (b) by the volume between the plates.
30,72
(d) Determine the capacitance of this arrangement.
nF
(e) Calculate the total energy from U = 2Cv2, and compare your answer with your result from Part (c).
Transcribed Image Text:An air-gap parallel-plate capacitor that has a plate area of 1.20 m2 and a separation of 1.40 mm is charged to 90 v. (a) What is the electric field between the plates? V kV/m 64.285 (b) What is the electric energy density between the plates? 18.28 v m)/m3 (c) Find the total energy by multiplying your answer from Part (b) by the volume between the plates. 30,72 (d) Determine the capacitance of this arrangement. nF (e) Calculate the total energy from U = 2Cv2, and compare your answer with your result from Part (c).
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