An aluminum can is to be constructed to contain 2400 cm3 of liquid. Let r and h be the radius of the base and the height of the can respectively. Find the radius of the base (r) and height of the can (h) that will minimize the amount of materials necessary to construct the can. The volume of a cylinder is given by V = Tr2h and the surface area is A = 2rrh + 27r?.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter9: Surfaces And Solids
Section9.3: Cylinders And Cones
Problem 40E: For a right circular cone, the dimensions are r=6 cm and h=8 cm. If the length of the radius is...
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An aluminum can is to be constructed to contain 2400 cm³ of liquid.
Let r and h be the radius of the base and the height of the can respectively.
Find the radius of the base (r) and height of the can (h) that will minimize the amount of materials necessary to construct the can. The
volume of a cylinder is given by V = Tr²h and the surface area is A = 2rrh + 2rr2.
r =
h =
Transcribed Image Text:An aluminum can is to be constructed to contain 2400 cm³ of liquid. Let r and h be the radius of the base and the height of the can respectively. Find the radius of the base (r) and height of the can (h) that will minimize the amount of materials necessary to construct the can. The volume of a cylinder is given by V = Tr²h and the surface area is A = 2rrh + 2rr2. r = h =
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