An archer shoots an arrow toward a 3.00 x 102 - g targetthat is sliding in her direction at a speed of 2.50 m/s on asmooth, slippery surface. The 22.5-g arrow is shot with a speedof 35.0 m/s and passes through the target, which is stoppedby the impact. What is the speed of the arrow after passingthrough the target?

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A: Given that:Mass of the ball, m=2.0 kgInitial speed, u=8.0 m/sFinal speed, v=6.0 m/s

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A: Given: m=0·45 kg vinitial=+38 m/s vfinal =-28 m/s Impulse is defined as change in momentum and can…

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A: Solution-

Q: A 80.0 kg archer, standing on frictionless ice, shoots a 90.0 g arrow at a speed of 50 m/s.

A: conservation of momentum, wherein the amount of recoil would be equal to that of the momentum of the…

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A: a) The required impulse is,

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A: The given values are, m1=18.0 g=0.018 kgm2=43.0 g=0.043 kgh=32.0 mv0=60.0 m/s

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A: It is given that,

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A: Here, using the conservation of momentum,

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A: Given:Mass of bullet = 29 g = 0.029 kgMass of target = 370 kgInitial velocity of bullet = 1200…

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A: The concept of head on elastic collision is used here.

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A: The impulse is same as change in momentum. that is, J=mu-mv

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A: Mass of the ship = m Mass of the iceberg = 10m The velocity of the ship before collision = v…

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A:

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A: Write the given data. mball=1.2 kgvi,ball=-14 m/sLi,bat=24 kgm/s

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A: SOlution: Given that Mass of projectile mp = 29 g =0.029 kg mass of box mb = 8.5 kg vp = 312 i m/s…

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A: The free body diagram is

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A: Given   ms of wooden block = 2.8 kg mass of bullet = 3.0 g speed of bullet before collision = 510…

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A:

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A: Given: