An archer shoots an arrow toward a 300-g target that is sliding in her direction at a speed of 2.00 m/s on a smooth, slippery surface. The 22.5-g arrow is shot with aspeed of 36.5 m/s and passes through the target, which is stopped by the impact. What is the speed of the arrow after passing through the target?m/s An estimated force vs. time curve for a baseball struck by a bat is shown in the figure below.Fmax = 18 000 NF (N)A20 00015 000100005 000t(ms)21(a) From this curve, determine the impulse delivered to the ballN S(b) From this curve, determine the average force exerted on the ballkN

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Asked Oct 28, 2019
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An archer shoots an arrow toward a 300-g target that is sliding in her direction at a speed of 2.00 m/s on a smooth, slippery surface. The 22.5-g arrow is shot with a
speed of 36.5 m/s and passes through the target, which is stopped by the impact. What is the speed of the arrow after passing through the target?
m/s
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An archer shoots an arrow toward a 300-g target that is sliding in her direction at a speed of 2.00 m/s on a smooth, slippery surface. The 22.5-g arrow is shot with a speed of 36.5 m/s and passes through the target, which is stopped by the impact. What is the speed of the arrow after passing through the target? m/s

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An estimated force vs. time curve for a baseball struck by a bat is shown in the figure below.
Fmax = 18 000 N
F (N)
A
20 000
15 000
10000
5 000
t(ms)
2
1
(a) From this curve, determine the impulse delivered to the ball
N S
(b) From this curve, determine the average force exerted on the ball
kN
help_outline

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An estimated force vs. time curve for a baseball struck by a bat is shown in the figure below. Fmax = 18 000 N F (N) A 20 000 15 000 10000 5 000 t(ms) 2 1 (a) From this curve, determine the impulse delivered to the ball N S (b) From this curve, determine the average force exerted on the ball kN

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Expert Answer

Step 1

Since we only answer the first question, we’ll answer the first one. Please resubmit the question and specify the other question you’d like answered.

Given, subscript 1 is for target and 2 is for arrow i.e.:

m = 0.30 kg
m, = 0.0225 kg
-2.00 m/s(negative because target is coming towards archer)
= 36.5 m/s
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m = 0.30 kg m, = 0.0225 kg -2.00 m/s(negative because target is coming towards archer) = 36.5 m/s

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Step 2

Using the definition of momentum (p) and law of conservation of linear momentum which states initial momentum (pi) equals final momentum (pf) we get:

P P
|(mv+m,v2) = (m,y, +m,v,),
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P P |(mv+m,v2) = (m,y, +m,v,),

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Step 3

After the impact the target momentum will be z...

(ту, + m,у,), — т, (v,),
(mу, + m,v,),
(v),
т,
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(ту, + m,у,), — т, (v,), (mу, + m,v,), (v), т,

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