An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40 ft per sec. The height s of the ball in feet isgiven by the equation s =-2.7t + 40t + 6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b.a. After how many seconds is the ball 22 ft above the moon's surface?After seconds the ball will be 22 ft above the moon's surface.(Round to the nearest hundredth as needed. Use a comma to separate answers as needed.)2

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Asked Jan 21, 2019
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An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40 ft per sec. The height s of the ball in feet is
given by the equation s =-2.7t + 40t + 6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b.
a. After how many seconds is the ball 22 ft above the moon's surface?
After seconds the ball will be 22 ft above the moon's surface.
(Round to the nearest hundredth as needed. Use a comma to separate answers as needed.)
2
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An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40 ft per sec. The height s of the ball in feet is given by the equation s =-2.7t + 40t + 6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 22 ft above the moon's surface? After seconds the ball will be 22 ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.) 2

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a) Calculating the time after which bal...

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