An axial load P is applied to a 220"-long bar with stepped cross-section as shown in Fig. 1. The area of each cross-section is shown in the figure. The stress-strain relation for the material used can be expressed as follows: 20,000€ 1+ 400€ 0 = 0 ≤ ≤ 0.03 (0 = ksi) in which the strain & is nondimensional and o has units of kips per square inch (ksi). You may assume that the elastic modulus is the same for the entire bar and is equal to the slope of the stress- strain curve at the origin. Determine the axial elongation (in inch) and strain (in %) of the bar if P = 30 kips A₁ = 5 in² A-15 in2

Mechanics of Materials (MindTap Course List)
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ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
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Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...
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An axial load P is applied to a 220"-long bar with stepped cross-section as shown in Fig. 1. The
area of each cross-section is shown in the figure. The stress-strain relation for the material used
can be expressed as follows:
0 ≤ ≤ 0.03 (0 = ksi)
in which the strain & is nondimensional and o has units of kips per square inch (ksi). You may
assume that the elastic modulus is the same for the entire bar and is equal to the slope of the stress-
strain curve at the origin.
Determine the axial elongation (in inch) and strain (in %) of the bar if P = 30 kips
t
20,000ε
1 + 400ε
0 =
A₁ = 5 in²
40 in
A₂ = 1.5 in²
180 in
Transcribed Image Text:An axial load P is applied to a 220"-long bar with stepped cross-section as shown in Fig. 1. The area of each cross-section is shown in the figure. The stress-strain relation for the material used can be expressed as follows: 0 ≤ ≤ 0.03 (0 = ksi) in which the strain & is nondimensional and o has units of kips per square inch (ksi). You may assume that the elastic modulus is the same for the entire bar and is equal to the slope of the stress- strain curve at the origin. Determine the axial elongation (in inch) and strain (in %) of the bar if P = 30 kips t 20,000ε 1 + 400ε 0 = A₁ = 5 in² 40 in A₂ = 1.5 in² 180 in
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