Question
Asked Sep 22, 2019
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An eagle is flying horizontally at 9.0 m/s with a fish in its claws. It accidentally drops the fish. (a) How much time passes before the fish's speed doubles? (b) How much additional time would be required for the speed to double again?

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Expert Answer

Step 1

The fish is initially moving horizontally at 9.0 m/s with no vertical velocity. When the eagle drops the fish then fish is accelerated downward by gravity at 9.8 m/s2.

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Initial horizontal speed u 9.0 m/s Final speed v 2u m/s 18.0 m/s Gravity g 9.8 m/s2

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Step 2

Part (a): Time passes before the fish's speed gets double.

Final speed

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2 х (18)* - (9)* + и,; uV324 81 u, 15.59 m/s У

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Step 3

uy is vertical speed. N...

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Initial vertical speed is zero.) gt и. и 15.59 9.8 1.5908 =1.6 s bл

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