An electrochemical cell is based on these two half-reactions: Oxidation: Cu(s) → Cu2+(aq, 0.010 M) + 2 e− Reduction: MnO4 −(aq, 2.0 M) + 4 H+(aq, 1.0 M) + 3 e− → MnO2(s) + 2 H2O(l) Calculate the cell potential.

Fundamentals Of Analytical Chemistry
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Chapter19: Applications Of Standard Electrode Potentials
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An electrochemical cell is based on these two half-reactions:

Oxidation: Cu(s) → Cu2+(aq, 0.010 M) + 2 e−

Reduction: MnO4 −(aq, 2.0 M) + 4 H+(aq, 1.0 M) + 3 e− → MnO2(s) + 2 H2O(l)

Calculate the cell potential.

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