An elevator loaded with tourists has a mass of 1750 kg.a.) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.55 m/s2 for 2.3 s. Calculate the tension in the cable supporting the elevator in newtonsb.) The elevator continues upward at constant velocity for 8.5 s. What is the tension in the cable, in Newtons, during this time?c.) The elevator experiences a negative acceleration at a rate of 0.65 m/s2 for 2.6 s. What is the tension in the cable, in Newtons, during this period of negative accleration?d.)   How far, in meters, has the elevator moved above its original starting point?

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Asked Oct 4, 2019
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An elevator loaded with tourists has a mass of 1750 kg.

a.) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.55 m/s2 for 2.3 s. Calculate the tension in the cable supporting the elevator in newtons

b.) The elevator continues upward at constant velocity for 8.5 s. What is the tension in the cable, in Newtons, during this time?

c.) The elevator experiences a negative acceleration at a rate of 0.65 m/s2 for 2.6 s. What is the tension in the cable, in Newtons, during this period of negative accleration?

d.)   How far, in meters, has the elevator moved above its original starting point?

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Expert Answer

Step 1

The free body diagram of the elevator of mass M is given below .

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уmg Σ

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Step 2

(a)  Write the expression for tension in the cable.

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(a) Write the expressipn for tension in the cable. From the free body diagram T- Mg Ma T MaMg = M(a+g) =(1750kg) (1.55m/s2)+(9.8m/s2 19862.5 N

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Step 3

(b)  Write the expression for tension in the cable if the ...

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From the free body diagram if the elevator moves upward with constant velocity then it has zero acceleration . Т-Mg 3D0 T Mg (1750kg)x(9.8m/s) -17150N

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