An excavation was made in sandy soil and soilsamples were collected at depths of 2ft 4ft,and 6 ft. Ground water was encountered at depth of 5 ft. Soil sample at 2ftwas dry. Soilsample at 4ft was tested in the lab and moisture content of 8.3% was determined. Assuming void ratio of 0.5 determine:a)Unit weight (lb/ft3) of soil at 2ft(110.24pcf)b)Unit weight (lb/ft3) of soil at 4ft(119.39pcf)c)Moisture content (%) of soil at 6ft(18.87%)

Question
Asked Sep 27, 2019
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An excavation was made in sandy soil and soil
samples were collected at depths of 2ft 4ft,
and 6 ft. Ground water was encountered at depth of 5 ft. Soil sample at 2ft
was dry. Soilsample at 4ft was tested in the lab and moisture content of 8.3% was determined. Assuming void ratio of 0.5 determine:
a)Unit weight (lb/ft3) of soil at 2ft(110.24pcf)
b)Unit weight (lb/ft3) of soil at 4ft(119.39pcf)
c)Moisture content (%) of soil at 6ft(18.87%)
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Expert Answer

Step 1

We have been given the following information:

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voidratio (e) 0.5 specific gravity (G)=2.65(sandy soil) water content (w)=8.3%(at4 ft) water content w)=0(at2 ft) lb unit weight of water 62.4-

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Step 2

With given data we can draw the following diagram:

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ground level 2ft 4ft 5ft 6ft groung water level

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Step 3

a) Bulk unit weight at 2ft: ...

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(G+eS)y 1+e (2.65+0.5x0)62.4 1+0.5 (2.65 x 62.4) 1.5 lb =110.656 ft

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