Question

Asked Jan 23, 2020

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An He^{1+} ion absorbs a photon with a frequency of 2.53 x 10^{18} Hz. If the energy of the final state is 4.35 x 10^{-15 }J, calculate the energy of the initial state.

Step 1

Frequency of photon = 2.53×10^{18} Hz

Energy of final state (E_{f}) = 4.35×10^{-15} J

Step 2

The change in energy can be expressed as the product of a constant that is plank’s constant(h) and frequency(ν). The mathematical expression for this is given as:

Step 3

Plugging the value of frequency, plank’s constant(h), and energy of ...

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